English

Frank solutions for Mathematics Part 2 [English] Class 10 ICSE chapter 20 - Trigonometry [Latest edition]

Advertisements

Chapters

Frank solutions for Mathematics Part 2 [English] Class 10 ICSE chapter 20 - Trigonometry - Shaalaa.com
Advertisements

Solutions for Chapter 20: Trigonometry

Below listed, you can find solutions for Chapter 20 of CISCE Frank for Mathematics Part 2 [English] Class 10 ICSE.


Exercise 21.1Exercise 21.2Exercise 21.3
Exercise 21.1

Frank solutions for Mathematics Part 2 [English] Class 10 ICSE 20 Trigonometry Exercise 21.1

1.01

Prove the following identity :

`(1 - sin^2θ)sec^2θ = 1`

1.02

Prove the following identity :

`(1 - cos^2θ)sec^2θ = tan^2θ`

1.03

Prove the following identity :

tanA+cotA=secAcosecA 

1.04

Prove the following identity :

`sinθ(1 + tanθ) + cosθ(1 +cotθ) = secθ + cosecθ` 

1.05

Prove the following identity :

 ( 1 + cotθ - cosecθ) ( 1 + tanθ + secθ) 

1.06

Prove the following identity :

sinθcotθ + sinθcosecθ = 1 + cosθ  

1.07

Prove the following identity :

secA(1 - sinA)(secA + tanA) = 1

1.08

Prove the following identity :

secA(1 + sinA)(secA - tanA) = 1

1.09

Prove the following identity :

cosecθ(1 + cosθ)(cosecθ - cotθ) = 1

1.1

Prove the following identity : 

`(secA - 1)/(secA + 1) = (1 - cosA)/(1 + cosA)`

1.11

Prove the following identity :

`(1 + sinA)/(1 - sinA) = (cosecA + 1)/(cosecA - 1)`

1.12

Prove the following identity:

`cosA/(1 + sinA) = secA - tanA`

1.13

Prove the following identity :

`(tanθ + secθ - 1)/(tanθ - secθ + 1) = (1 + sinθ)/(cosθ)`

2.01

Prove the following identity : 

`sin^2Acos^2B - cos^2Asin^2B = sin^2A - sin^2B`

2.02

Prove the following identity :

`(1 - tanA)^2 + (1 + tanA)^2 = 2sec^2A`

2.03

Prove the following identity :

`cosec^4A - cosec^2A = cot^4A + cot^2A`

2.04

Prove the following identity :

`sec^2A + cosec^2A = sec^2Acosec^2A`

2.05

Prove the following identity :

`cos^4A - sin^4A = 2cos^2A - 1`

2.06

Prove the following identity:

tan2A − sin2A = tan2A · sin2A

2.07

Prove the following identity :

(secA - cosA)(secA + cosA) = `sin^2A + tan^2A`

2.08

Prove the following identity :

`(cosA + sinA)^2 + (cosA - sinA)^2 = 2`

2.09

Prove the following identity :

`(cosecA - sinA)(secA - cosA)(tanA + cotA) = 1`

2.1

Prove the following identity :

`sec^2A.cosec^2A = tan^2A + cot^2A + 2`

2.11

Prove the following identity : 

`(cotA + cosecA - 1)/(cotA - cosecA + 1) = (cosA + 1)/sinA`

2.12

Prove the following identity : 

`cosA/(1 - tanA) + sinA/(1 - cotA) = sinA + cosA`

2.13

Prove the following identity : 

`(cosecA - sinA)(secA - cosA) = 1/(tanA + cotA)`

2.14

Prove the following identity : 

`sin^4A + cos^4A = 1 - 2sin^2Acos^2A`

2.15

Prove the following Identities :

`(cosecA)/(cotA+tanA)=cosA`

2.16

Prove the following identities:

`(tan"A"+tan"B")/(cot"A"+cot"B")=tan"A"tan"B"`

2.17

Prove the following identities:

`(sec"A"-1)/(sec"A"+1)=(sin"A"/(1+cos"A"))^2`

3.01

Prove the following identity : 

`sinA/(1 + cosA) + (1 + cosA)/sinA = 2cosecA`

3.02

Prove the following identity :

`(1 + cosA)/(1 - cosA) = (cosecA + cotA)^2`

3.03

Prove the following identity :

`(cotA + tanB)/(cotB + tanA) = cotAtanB`

3.04

Prove the following identity :

`1/(tanA + cotA) = sinAcosA`

3.05

Prove the following identity :

`tanA - cotA = (1 - 2cos^2A)/(sinAcosA)`

3.06

Prove the following identity : 

`((1 + tan^2A)cotA)/(cosec^2A) = tanA`

3.07

Prove the following identity : 

`cosecA + cotA = 1/(cosecA - cotA)`

3.08

Prove the following identity : 

`(cosecA)/(cosecA - 1) + (cosecA)/(cosecA + 1) = 2sec^2A`

3.09

Prove the following identity : 

`(1 + cosA)/(1 - cosA) = tan^2A/(secA - 1)^2`

3.1

Prove the following identity : 

`(cotA - cosecA)^2 = (1 - cosA)/(1 + cosA)`

4.01

Prove the following identity : 

`sqrt(cosec^2q - 1) = "cosq  cosecq"`

4.02

Prove the following identity : 

`sqrt((1 + sinq)/(1 - sinq)) + sqrt((1- sinq)/(1 + sinq))` = 2secq

4.03

Prove the following identity : 

`sqrt((1 - cosA)/(1 + cosA)) = sinA/(1 + cosA)`

4.04

Prove the following identity : 

`sqrt((1 + cosA)/(1 - cosA)) = cosecA + cotA`

4.05

Prove the following identity : 

`sqrt((secq - 1)/(secq + 1)) + sqrt((secq + 1)/(secq - 1))` = 2 cosesq

5.01

Prove the following identity : 

`(secθ - tanθ)^2 = (1 - sinθ)/(1 + sinθ)`

5.02

Prove the following identity : 

`1/(sinA + cosA) + 1/(sinA - cosA) = (2sinA)/(1 - 2cos^2A)`

5.03

Prove the following identity : 

`(sinA + cosA)/(sinA - cosA) + (sinA - cosA)/(sinA + cosA) = 2/(2sin^2A - 1)`

5.04

Prove the following identity : 

`tan^2A - tan^2B = (sin^2A - sin^2B)/(cos^2Acos^2B)`

5.05

Prove the following identity : 

`cosA/(1 - tanA) + sin^2A/(sinA - cosA) = cosA + sinA`

5.06

Prove the following identity : 

`(1 + tan^2A) + (1 + 1/tan^2A) = 1/(sin^2A - sin^4A)`

5.07

Prove the following identity : 

`(cos^3A + sin^3A)/(cosA + sinA) + (cos^3A - sin^3A)/(cosA - sinA) = 2`

5.08

Prove the following identity : 

`(tanθ + 1/cosθ)^2 + (tanθ - 1/cosθ)^2 = 2((1 + sin^2θ)/(1 - sin^2θ))`

5.09

Prove the following identity : 

`(sinA - sinB)/(cosA + cosB) + (cosA - cosB)/(sinA + sinB) = 0`

5.1

Prove the following identity : 

`1/(cosA + sinA - 1) + 2/(cosA + sinA + 1) = cosecA + secA`

5.11

Prove the following identity : 

`(cotA + cosecA - 1)/(cotA - cosecA + 1) = (cosA + 1)/sinA`

5.12

Prove the following identity :

`(secA - 1)/(secA + 1) = sin^2A/(1 + cosA)^2`

6.01

Prove the following identity  :

`(1 + cotA)^2 + (1 - cotA)^2 = 2cosec^2A`

6.02

Prove the following identity : 

`(cosecθ)/(tanθ + cotθ) = cosθ`

6.03

Prove the following identity : 

`(1 + tan^2θ)sinθcosθ = tanθ`

6.04

Prove the following identity : 

`(1 + sinθ)/(cosecθ - cotθ) - (1 - sinθ)/(cosecθ + cotθ) = 2(1 + cotθ)`

6.05

Prove the following identity : 

`(1 + cotA + tanA)(sinA - cosA) = secA/(cosec^2A) - (cosecA)/sec^2A`

6.06

Prove the following identity : 

`2(sin^6θ + cos^6θ) - 3(sin^4θ + cos^4θ) + 1 = 0`

6.07

Prove the following identity : 

`sin^8θ - cos^8θ = (sin^2θ - cos^2θ)(1 - 2sin^2θcos^2θ)`

6.08

Prove the following identity : 

`sec^4A - sec^2A = sin^2A/cos^4A`

6.09

Prove the following identity :

`tan^2θ/(tan^2θ - 1) + (cosec^2θ)/(sec^2θ - cosec^2θ) = 1/(sin^2θ - cos^2θ)`

6.1

Prove the following identity :

`(sec^2θ - sin^2θ)/tan^2θ = cosec^2θ - cos^2θ`

6.11

Prove the following identity :

`(cos^3θ + sin^3θ)/(cosθ + sinθ) + (cos^3θ - sin^3θ)/(cosθ - sinθ) = 2`

6.12

Prove the following identity :

`(tanθ + sinθ)/(tanθ - sinθ) = (secθ + 1)/(secθ - 1)`

6.13

Prove the following identity : 

`[1/((sec^2θ - cos^2θ)) + 1/((cosec^2θ - sin^2θ))](sin^2θcos^2θ) = (1 - sin^2θcos^2θ)/(2 + sin^2θcos^2θ)`

6.14

Prove the following identity :

`(cot^2θ(secθ - 1))/((1 + sinθ)) = sec^2θ((1-sinθ)/(1 + secθ))`

Exercise 21.2

Frank solutions for Mathematics Part 2 [English] Class 10 ICSE 20 Trigonometry Exercise 21.2

1

If m = a secA + b tanA and n = a tanA + b secA , prove that m2 - n2 = a2 - b2

2

If `x/(a cosθ) = y/(b sinθ)   "and"  (ax)/cosθ - (by)/sinθ = a^2 - b^2 , "prove that"  x^2/a^2 + y^2/b^2 = 1`

3

If x = r sinA cosB , y = r sinA sinB and z = r cosA , prove that   `x^2 + y^2 + z^2 = r^2`

4

If sinA + cosA = m and secA + cosecA = n , prove that n(m2 - 1) = 2m

5

If x = acosθ , y = bcotθ , prove that `a^2/x^2 - b^2/y^2 = 1.`

6

If secθ + tanθ = m , secθ - tanθ = n , prove that mn = 1

7

If x = asecθ + btanθ and y = atanθ + bsecθ , prove that `x^2 - y^2 = a^2 - b^2`

8

If tanA + sinA = m and tanA - sinA = n , prove that (`m^2 - n^2)^2` = 16mn 

9

If sinA + cosA = `sqrt(2)` , prove that sinAcosA = `1/2`

10

If `asin^2θ + bcos^2θ = c and p sin^2θ + qcos^2θ = r` , prove that (b - c)(r - p) = (c - a)(q - r)

Exercise 21.3

Frank solutions for Mathematics Part 2 [English] Class 10 ICSE 20 Trigonometry Exercise 21.3

1.01

Without using trigonometric table , evaluate : 

`cosec49°cos41° + (tan31°)/(cot59°)`

1.02

Without using trigonometric table , evaluate : 

`(sin47^circ/cos43^circ)^2 - 4cos^2 45^circ + (cos43^circ/sin47^circ)^2`

1.03

Without using trigonometric table , evaluate : 

`cos90^circ + sin30^circ tan45^circ cos^2 45^circ`

1.04

Without using trigonometric table , evaluate : 

`(sin49^circ/sin41^circ)^2 + (cos41^circ/sin49^circ)^2`

1.05

Without using trigonometric table , evaluate : 

`sin72^circ/cos18^circ  - sec32^circ/(cosec58^circ)`

2.01

Find the value of `θ(0^circ < θ < 90^circ)` if : 

`cos 63^circ sec(90^circ - θ) = 1`

2.02

Find the value of `θ(0^circ < θ < 90^circ)` if : 

`tan35^circ cot(90^circ - θ) = 1`

3.01

Without using trigonometric identity , show that :

`sin42^circ sec48^circ + cos42^circ cosec48^circ = 2`

3.02

Without using trigonometric identity , show that :

`tan10^circ tan20^circ tan30^circ tan70^circ tan80^circ = 1/sqrt(3)`

3.03

Without using trigonometric identity , show that :

`sin(50^circ + θ) - cos(40^circ - θ) = 0`

3.04

Without using trigonometric identity , show that :

`cos^2 25^circ + cos^2 65^circ = 1`

3.05

Without using trigonometric identity , show that :

`sec70^circ sin20^circ - cos20^circ cosec70^circ = 0`

4

Prove that `sinA/sin(90^circ - A) + cosA/cos(90^circ - A) = sec(90^circ - A) cosec(90^circ - A)`

5.01

For ΔABC , prove that : 

`tan ((B + C)/2) = cot "A/2`

5.02

For ΔABC , prove that : 

`sin((A + B)/2) = cos"C/2`

6

Prove that  `sin(90^circ - A).cos(90^circ - A) = tanA/(1 + tan^2A)`

7

Find the value of x , if `cosx = cos60^circ cos30^circ - sin60^circ sin30^circ`

8

Find x , if `cos(2x - 6) = cos^2 30^circ - cos^2 60^circ`

9

Given `cos38^circ sec(90^circ - 2A) = 1` , Find the value of <A

10

prove that `1/(1 + cos(90^circ - A)) + 1/(1 - cos(90^circ - A)) = 2cosec^2(90^circ - A)`

Solutions for 20: Trigonometry

Exercise 21.1Exercise 21.2Exercise 21.3
Frank solutions for Mathematics Part 2 [English] Class 10 ICSE chapter 20 - Trigonometry - Shaalaa.com

Frank solutions for Mathematics Part 2 [English] Class 10 ICSE chapter 20 - Trigonometry

Shaalaa.com has the CISCE Mathematics Mathematics Part 2 [English] Class 10 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. Frank solutions for Mathematics Mathematics Part 2 [English] Class 10 ICSE CISCE 20 (Trigonometry) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. Frank textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics Part 2 [English] Class 10 ICSE chapter 20 Trigonometry are Trigonometric Ratios, Relation Among Trigonometric Ratios, Trigonometric Ratios of Complementary Angles, Application of Trigonometric Tables, Trigonometric Identities (Square Relations), Elimination of Trigonometrical Ratios.

Using Frank Mathematics Part 2 [English] Class 10 ICSE solutions Trigonometry exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Frank Solutions are essential questions that can be asked in the final exam. Maximum CISCE Mathematics Part 2 [English] Class 10 ICSE students prefer Frank Textbook Solutions to score more in exams.

Get the free view of Chapter 20, Trigonometry Mathematics Part 2 [English] Class 10 ICSE additional questions for Mathematics Mathematics Part 2 [English] Class 10 ICSE CISCE, and you can use Shaalaa.com to keep it handy for your exam preparation.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×