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Question
Prove the following identity :
`(1 + sinA)/(1 - sinA) = (cosecA + 1)/(cosecA - 1)`
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Solution
LHS = `(1 + sinA)/(1 - sinA)`
RHS = `(cosecA + 1)/(cosecA - 1) = (1/sinA + 1)/(1/sinA - 1)`
= `(1 + sinA)/(1 - sinA)`
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RELATED QUESTIONS
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tan (90 – θ) = ?
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Prove that `(1 + sec theta - tan theta)/(1 + sec theta + tan theta) = (1 - sin theta)/cos theta`
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Solution :
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= `cosθ/sinθ + sinθ/cosθ`
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L.H.S. = R.H.S
∴ cotθ + tanθ = cosecθ × secθ
