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Factorise the following:
(2a - b)2 -9(3c - d)2
Concept: undefined >> undefined
Factorise the following:
b2 - 2bc + c2 - a2
Concept: undefined >> undefined
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Factorise the following:
`x^2 + (1)/x^2 - 2`
Concept: undefined >> undefined
Factorise the following:
(x2 + y2 – z2)2 – 4x2y2
Concept: undefined >> undefined
Factorise the following:
a2 + b2 – c2 – d2 + 2ab – 2cd
Concept: undefined >> undefined
Factorise the following:
4xy - x2 - 4y2 + z2
Concept: undefined >> undefined
Factorise the following:
4x2 - 12ax - y2 - z2 - 2yz + 9a2
Concept: undefined >> undefined
Factorise the following:
(x + y)3 - x - y
Concept: undefined >> undefined
Factorise the following:
y4 + y2 + 1
Concept: undefined >> undefined
Factorise the following:
(a2 – b2)(c2 – d2) – 4abcd
Concept: undefined >> undefined
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
Concept: undefined >> undefined
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
Concept: undefined >> undefined
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
Concept: undefined >> undefined
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: QR = QT
Concept: undefined >> undefined
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: RT bisects angle R
Concept: undefined >> undefined
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: ∠RTS = 90°
Concept: undefined >> undefined
ABCD is a parallelogram. The bisector of ∠BAD meets DC at P, and AD is half of AB.
Prove that: BP bisects ∠ABC.
Concept: undefined >> undefined
ABCD is a parallelogram. The bisector of ∠BAD meets DC at P, and AD is half of AB.
Prove that: ∠APB is a right angle.
Concept: undefined >> undefined
In the given figure, MP is the bisector of ∠P and RN is the bisector of ∠R of parallelogram PQRS. Prove that PMRN is a parallelogram.
Concept: undefined >> undefined
In a parallelogram ABCD, E is the midpoint of AB and DE bisects angle D. Prove that: BC = BE.
Concept: undefined >> undefined
