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Question
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: RT bisects angle R
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Solution
Since QT = QR
∠QTR = ∠QRT
But ∠QTR = ∠TRS ...(alternate angles ∵ SR || PQ)
⇒ ∠QRT = ∠TRS
Therefore, RT bisects ∠R.
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