Advertisements
Advertisements
Question
Construct a parallelogram POUR in which, PO = 5.5 cm, OU = 7.2 cm and ∠O = 70°.
Advertisements
Solution
Since, opposite sides of a parallelogram are equal.
∴ PO = RU = 5.5 cm, OU = RP = 7.2 cm
Steps of construction:
Step I: Draw PO = 5.5 cm.
Step II: Construct ∠POX = 70°.
Step III: With O as centre and radius OU = 7.2 cm, draw an arc.
Step IV: WIth U as centre and radius UR = 5.5 cm, draw an arc.
Step V: With P as centre and radius PR = 7.2 cm, draw an arc to cut the arc drawn in Step IV.
Step VI: Join PR and UR.
Hence, POUR is the required parallelogram.
APPEARS IN
RELATED QUESTIONS
The alongside figure shows a parallelogram ABCD in which AE = EF = FC.
Prove that:
- DE is parallel to FB
- DE = FB
- DEBF is a parallelogram.
Prove that the bisectors of opposite angles of a parallelogram are parallel.
The following figure shows a trapezium ABCD in which AB is parallel to DC and AD = BC. 
Prove that:
(i) ∠DAB = ∠CBA
(ii) ∠ADC = ∠BCD
(iii) AC = BD
(iv) OA = OB and OC = OD.
In parallelogram ABCD, the bisector of angle A meets DC at P and AB = 2 AD.
Prove that:
(i) BP bisects angle B.
(ii) Angle APB = 90o.
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: QR = QT
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: RT bisects angle R
In a parallelogram ABCD, E is the midpoint of AB and DE bisects angle D. Prove that:CE is the bisector of angle C and angle DEC is a right angle
In the given figure, the perimeter of parallelogram PQRS is 42 cm. Find the lengths of PQ and PS.
Find the perimeter of the parallelogram PQRS.
In parallelogram ABCD of the accompanying diagram, line DP is drawn bisecting BC at N and meeting AB (extended) at P. From vertex C, line CQ is drawn bisecting side AD at M and meeting AB (extended) at Q. Lines DP and CQ meet at O. Show that the area of triangle QPO is `9/8` of the area of the parallelogram ABCD
