Advertisements
Advertisements
प्रश्न
Construct a parallelogram POUR in which, PO = 5.5 cm, OU = 7.2 cm and ∠O = 70°.
Advertisements
उत्तर
Since, opposite sides of a parallelogram are equal.
∴ PO = RU = 5.5 cm, OU = RP = 7.2 cm
Steps of construction:
Step I: Draw PO = 5.5 cm.
Step II: Construct ∠POX = 70°.
Step III: With O as centre and radius OU = 7.2 cm, draw an arc.
Step IV: WIth U as centre and radius UR = 5.5 cm, draw an arc.
Step V: With P as centre and radius PR = 7.2 cm, draw an arc to cut the arc drawn in Step IV.
Step VI: Join PR and UR.
Hence, POUR is the required parallelogram.
APPEARS IN
संबंधित प्रश्न
In the given figure, ABCD is a parallelogram.
Prove that: AB = 2 BC.
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: RT bisects angle R
PQRS is a parallelogram. T is the mid-point of PQ and ST bisects ∠PSR.
Prove that: ∠RTS = 90°
ABCD is a parallelogram. The bisector of ∠BAD meets DC at P, and AD is half of AB.
Prove that: BP bisects ∠ABC.
In a parallelogram ABCD, E is the midpoint of AB and DE bisects angle D. Prove that:CE is the bisector of angle C and angle DEC is a right angle
Find the perimeter of the parallelogram PQRS.
In the Figure, ABCD is a rectangle and EFGH is a parallelogram. Using the measurements given in the figure, what is the length d of the segment that is perpendicular to `bar("HE")` and `bar("FG")`?
In parallelogram ABCD of the accompanying diagram, line DP is drawn bisecting BC at N and meeting AB (extended) at P. From vertex C, line CQ is drawn bisecting side AD at M and meeting AB (extended) at Q. Lines DP and CQ meet at O. Show that the area of triangle QPO is `9/8` of the area of the parallelogram ABCD
Which of the following statement is correct?
In the following figure, it is given that BDEF and FDCE are parallelograms. Can you say that BD = CD? Why or why not?
