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Factorise the following: (x2 + y2 – z2)2 – 4x2y2 - Mathematics

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Question

Factorise the following:

(x2 + y2 – z2)2 – 4x2y2

Sum
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Solution

(x2 + y2 – z2)2 – 4x2y2

= (x2 + y2 – z2)2 – (2xy)2

= (x2 + y2 – z2 – 2xy) (x2 + y2 – z2 + 2xy)

= [(x2 + y2 – 2xy) – z2] [(x2 + y2 + 2xy) – z2]

= [(x – y)2 – z2] [(x + y)2 – z2]

= [(x – y – z) (x – y + z)] [(x + y – z) (x + y + z)]

= (x – y – z) (x – y + z) (x + y – z) (x + y + z)

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Method of Factorisation : Difference of Two Squares
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Chapter 5: Factorisation - Exercise 5.3

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 5 Factorisation
Exercise 5.3 | Q 2.06
B Nirmala Shastry Mathematics [English] Class 9 ICSE
Chapter 4 Factorisation
EXERCISE 4B | Q VII. 2. | Page 43
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