Advertisements
Advertisements
प्रश्न
Factorise the following:
(x2 + y2 – z2)2 – 4x2y2
Advertisements
उत्तर
(x2 + y2 – z2)2 – 4x2y2
= (x2 + y2 – z2)2 – (2xy)2
= (x2 + y2 – z2 – 2xy) (x2 + y2 – z2 + 2xy)
= [(x2 + y2 – 2xy) – z2] [(x2 + y2 + 2xy) – z2]
= [(x – y)2 – z2] [(x + y)2 – z2]
= [(x – y – z) (x – y + z)] [(x + y – z) (x + y + z)]
= (x – y – z) (x – y + z) (x + y – z) (x + y + z)
संबंधित प्रश्न
Factorise : a2 - (2a + 3b)2
Factorise : 3a5 - 108a3
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : a2 - b2 - (a + b) 2
Factorize : 9a2 - (a2 - 4) 2
Factorise the following by the difference of two squares:
x2 - 16
Factorise the following by the difference of two squares:
(x + y)2 -1
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
a2 + b2 – c2 – d2 + 2ab – 2cd
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
