Advertisements
Advertisements
Question
Factorise : a2 ( b + c) - (b + c)3
Sum
Advertisements
Solution
a2 ( b + c) - (b + c)3
= ( b + c )[ a2 - ( b + c )2 ]
= ( b + c )[( a + b + c )( a - b - c )]
= ( b + c )( a + b + c )( a - b - c )
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : 4a2b - 9b3
Factorise : 4a2 - 49b2 + 2a - 7b
Factorise : 9a2 + 3a - 8b - 64b2
Factorise : a2 + b2 - c2 - d2 + 2ab - 2cd
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise : (x2 + 4y2 - 9z2)2 - 16x2y2
Factorise the following by the difference of two squares:
441 - 81y2
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following:
(2a - b)2 -9(3c - d)2
Express each of the following as the difference of two squares:
(x2 + 2x - 3) (x2 - 2x + 3)
