Advertisements
Advertisements
Question
Factorise the following:
a2 + b2 – c2 – d2 + 2ab – 2cd
Sum
Advertisements
Solution
a2 + b2 – c2 – d2 + 2ab – 2cd
= (a2 + b2 + 2ab) – (c2 + d2 + 2cd)
= (a + b)2 – (c + d)2
= (a + b + c + d) (a + b – c – d)
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
RELATED QUESTIONS
Factorise : a (a - 1) - b (b - 1)
Factorise: 4a2 - (4b2 + 4bc + c2)
Factorise : 4x2 - 12ax - y2 - z2 - 2yz + 9a2
Factorise : (a + b) 2 - a2 + b2
Factorise : a2 - b2 - (a + b) 2
Factorize : 9a2 - (a2 - 4) 2
Factorise the following by the difference of two squares:
x2 - 16
Factorise the following:
`x^2 + (1)/x^2 - 2`
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
Express each of the following as the difference of two squares:
(x2 - 2x + 3) (x2 - 2x - 3)
