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Question
Factorise the following:
16a2 – 9b2 + 30bc – 25c2
Sum
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Solution
Given: 16a2 – 9b2 + 30bc – 25c2
⇒ 16a2 – (9b2 – 30bc + 25c2)
⇒ 9a2 – 30bc + 25c2 = (3b – 5c)2
⇒ 16a2 – (3b – 5c)2
We know that,
(a + b)(a – b) = a2 – b2
(4a + 3b – 5c) (4a – 3b + 5c)
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