Factorise the Following: (2a - B)2 -9(3c - D)2

Factorise the following:
(2a - b)² -9(3c - d)²

Sum

(2a - b)² - 9(3c - d)²= (2a - b)² - [3(3c - d)]²= [(2a - b) - 3(3c - d)][(2a - b) + 3(3c - d)]
= (2a - b - 9c + 3d)(2a - b + 9c - 3d).

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Method of Factorisation : Difference of Two Squares

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Chapter 5: Factorisation - Exercise 5.3

Chapter 5 Factorisation
Exercise 5.3 | Q 2.03

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