Advertisements
Advertisements
Question
Factorise the following:
4xy - x2 - 4y2 + z2
Sum
Advertisements
Solution
4xy - x2 - 4y2 + z2
= z2 - x2 - 4y2 + 4xy
= z2 - (x2 + 4y2 - 4xy)
= z2 - (x - 2y)2
= [z - (x - 2y)][z + (x - 2y)]
= (z - x + 2y)(z + x - 2y).
shaalaa.com
Method of Factorisation : Difference of Two Squares
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorise : a3 + 2a2 - a - 2
Factorize : 9a2 - (a2 - 4) 2
Factorise : `x^2 + 1/x^2 - 11`
Factorise the following by the difference of two squares:
x2 - 16
Factorise the following by the difference of two squares:
`"m"^2 - (1)/(9)"n"^2`
Factorise the following by the difference of two squares:
x2 + y2 - z2 - 2xy
Factorise the following:
(2a - b)2 -9(3c - d)2
Factorise the following:
`x^2 + (1)/x^2 - 2`
Factorise the following:
(x + y)3 - x - y
Express each of the following as the difference of two squares:
(x2 - 2x + 3)(x2 + 2x + 3)
