Please select a subject first
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If u = `sin^-1 ((2x)/(1 + x^2))` and v = `tan^-1 ((2x)/(1 - x^2))`, then `"du"/"dv"` is ______.
Concept: undefined >> undefined
| COLUMN-I | COLUMN-II |
| (A) If a function f(x) = `{((sin3x)/x, "if" x = 0),("k"/2",", "if" x = 0):}` is continuous at x = 0, then k is equal to |
(a) |x| |
| (B) Every continuous function is differentiable | (b) True |
| (C) An example of a function which is continuous everywhere but not differentiable at exactly one point |
(c) 6 |
| (D) The identity function i.e. f (x) = x ∀ ∈x R is a continuous function |
(d) False |
Concept: undefined >> undefined
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|sinx| is a differentiable function for every value of x.
Concept: undefined >> undefined
cos |x| is differentiable everywhere.
Concept: undefined >> undefined
Show that the function f(x) = |sin x + cos x| is continuous at x = π.
Concept: undefined >> undefined
`sin sqrt(x) + cos^2 sqrt(x)`
Concept: undefined >> undefined
sinn (ax2 + bx + c)
Concept: undefined >> undefined
`cos(tan sqrt(x + 1))`
Concept: undefined >> undefined
sinx2 + sin2x + sin2(x2)
Concept: undefined >> undefined
`sin^-1 1/sqrt(x + 1)`
Concept: undefined >> undefined
(sin x)cosx
Concept: undefined >> undefined
sinmx . cosnx
Concept: undefined >> undefined
(x + 1)2(x + 2)3(x + 3)4
Concept: undefined >> undefined
`cos^-1 ((sinx + cosx)/sqrt(2)), (-pi)/4 < x < pi/4`
Concept: undefined >> undefined
`tan^-1 (sqrt((1 - cosx)/(1 + cosx))), - pi/4 < x < pi/4`
Concept: undefined >> undefined
`tan^-1 (secx + tanx), - pi/2 < x < pi/2`
Concept: undefined >> undefined
`tan^-1 (("a"cosx - "b"sinx)/("b"cosx - "a"sinx)), - pi/2 < x < pi/2` and `"a"/"b" tan x > -1`
Concept: undefined >> undefined
`sec^-1 (1/(4x^3 - 3x)), 0 < x < 1/sqrt(2)`
Concept: undefined >> undefined
`tan^-1 ((3"a"^2x - x^3)/("a"^3 - 3"a"x^2)), (-1)/sqrt(3) < x/"a" < 1/sqrt(3)`
Concept: undefined >> undefined
`tan^-1 ((sqrt(1 + x^2) + sqrt(1 - x^2))/(sqrt(1 + x^2) - sqrt(1 - x^2))), -1 < x < 1, x ≠ 0`
Concept: undefined >> undefined
