Advertisements
Advertisements
Question
When liquid ‘A’ is treated with a freshly prepared ammoniacal silver nitrate solution, it gives bright silver mirror. The liquid forms a white crystalline solid on treatment with sodium hydrogensulphite. Liquid ‘B’ also forms a white crystalline solid with sodium hydrogensulphite but it does not give test with ammoniacal silver nitrate. Which of the two liquids is aldehyde? Write the chemical equations of these reactions also.
Advertisements
Solution
Liquid ‘A’ forms a bright silver mirror on treatment with ammoniacal \[\ce{AgNO3}\] solution, therefore, liquid ‘A’ is an aldehyde.
Liquid B does not give test with ammoniacal \[\ce{AgNO3}\] solution, therefore, liquid ‘B’ must be a methyl ketone.
Chemical equations for these reactions are:
\[\begin{array}{cc}
\phantom{........}\ce{R}\phantom{......................}\ce{R}\phantom{.......}\ce{SO3Na}\phantom{}\\
\phantom{...}\backslash\phantom{......................}\backslash\phantom{...}\phantom{..}/\\\
\phantom{}\ce{C = O + NaHSO3 -> \phantom{..}C}\\
\phantom{.............}/\phantom{......................}/\phantom{.....}\backslash\phantom{..........}\\
\phantom{.....}\ce{\underset{Aldehyde(A)}{H}\phantom{................}\underset{(White crystalline solid)}{\phantom{.}H\phantom{.......}OH}}\phantom{..}
\end{array}\]
\[\begin{array}{cc}
\phantom{........}\ce{R}\phantom{......................}\ce{R}\phantom{.......}\ce{SO3Na}\phantom{}\\
\phantom{...}\backslash\phantom{......................}\backslash\phantom{...}\phantom{..}/\\\
\phantom{}\ce{C = O + NaHSO3 -> \phantom{..}C}\\
\phantom{.............}/\phantom{......................}/\phantom{.....}\backslash\phantom{..........}\\
\phantom{....}\ce{\underset{Methyl ketone (B)}{H3C}\phantom{.............}\underset{(White NaHSO3 adduct)}{\phantom{.}H3C\phantom{.......}OH}}\phantom{.....}
\end{array}\]
\[\ce{\underset{Aldehyde (A)}{R - CHO} + \underset{Tollens reagent}{2[Ag(NH3)2]+} OH- ->[Warm] RCOONH4 + \underset{(Silver mirror)}{2Ag + 3}NH3 + H2O}\]
\[\begin{array}{cc}
\ce{O}\phantom{...............................}\\
||\phantom{...............................}\\
\ce{\underset{Methyl ketone (B)}{R - C - CH3} ->[Tollens reagent] No silver mirror}
\end{array}\]
APPEARS IN
RELATED QUESTIONS
A compound 'A' of molecular formula C2H3OCl undergoes a series of reactions as shown below. Write the structures of A, B, C and D in the following reactions :

Write the products formed when CH3CHO reacts with the following reagents: CH3CHO in the presence of dilute NaOH
What is meant by the following term? Give an example of the reaction in the following case.
Aldol
How will you bring about the following conversion in not more than two steps?
Benzaldehyde to 3-Phenylpropan-1-ol
Give reasons Acetylation of aniline reduces its activation effect.
Write chemical equations of the following reaction :
Propanone is treated with dilute Ba (OH)2-.
What is substituted imine called?
Explain aldol condensation reaction in detail.
Compounds A and C in the following reaction are:
\[\ce{CH3CHO ->[(i) CH3MgBr][(ii) H2O] (A) ->[H2SO4, Δ] (B) ->[Hydroboration oxidation] (C)}\]
Assertion: Aromatic aldehydes and formaldehyde undergo Cannizaro reaction.
Reason: Aromatic aldehydes are almost as reactive as formaldehyde.
Which of the following gives aldol con~ensation reaction?
Identify A and B from the following reaction:
\[\begin{array}{cc}
\ce{CH3}\phantom{.................}\\
|\phantom{....................}\\
\phantom{}\ce{2CH3 - C = O ->[Ba(OH)2] A ->[Δ] B + H2O}
\end{array}\]
Predict the reagent for carrying out the following transformations:
Ethanal to 3-hydroxy butanal
\[\ce{CH3-CH2-CHO ->[dil][alkali] Product}\]
The product in the above reaction is:
Explain Aldol condensation of ethanal.
Which of the following compounds will undergo self-condensation in the presence of dilute NaOH solution?
Assertion (A): The final product in Aldol condensation is always α, β-unsaturated carbonyl compound.
Reason (R): α, β-unsaturated carbonyl compounds are stabilised due to conjugation.

Identify A and B:
Which one of the following undergoes reaction with 50% sodiumhydroxide solution to give the corresponding alcohol and acid:
