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Question
What is the ratio of volumes of H2 and O2 liberated during electrolysis of acidified water?
(A) 1 : 2
(B) 2 : 1
(C) 1 : 8
(D) 8 : 1
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Solution
2 : 1
The reaction occuring during electrolysis of acidified water is
Thus the ratio of number of moles (n) of H2 and O2 liberated is 2 : 1
But volume V ∝ n (∵ PV = nRT)
∴ The ratio of volumes of H2 and O2 liberated is 2 : 1
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