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Question
What will happen during the electrolysis of aqueous solution of \[\ce{CuSO4}\] by using platinum electrodes?
(i) Copper will deposit at cathode.
(ii) Copper will deposit at anode.
(iii) Oxygen will be released at anode.
(iv) Copper will dissolve at anode.
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Solution
(i) Copper will deposit at cathode.
(iii) Oxygen will be released at anode.
Explanation:
During electrolysis following reaction takes place at cathode:
\[\ce{Cu^{2+} + 2e^{-} -> Cu}\]
\[\ce{H^{-} + e^{-} -> 1/2 H_2}\]
Standard electrode potential of \[\ce{Cu^{2+}/Cu}\] is greater than \[\ce{H-/1/2 H2}\] therefore Cu will deposite at cathode.
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