Question

Time Required to deposite one millimole of aluminium metal by the passage of 9.65 ampere through aqueous solution of aluminium is

Options

• 30 sec.

• 10 sec.

• 30,000 sec.

• 10,000 sec.

Answer 1

30 Sec.

Explanation:

`Al3^{+} + 3^(e-) -> Al`

To deposite 1 mole of Al charge require = 3 × 96500C

To deposite 1 mill mole of Al charge required = `(3 xx 96500)/1000`

Time = `"Charge"/"Current" = (3 xx 96500)/1000` = 30 sec.