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Question
What is the action of following on ethyl bromide?
alcoholic sodium hydroxide
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Solution
When ethyl bromide is boiled with an alcoholic solution of sodium hydroxide \[\ce{(NaOH)}\], an alkene is formed due to the elimination of hydrogen atoms from carbon and halogen from α-carbon, which is called dehydrohalogenation.
\[\ce{\underset{(Ethyl bromide)}{\overset{\beta\phantom{.............}\alpha\phantom{............}}{CH3 - CH2 - Br}} + \underset{(alc.)}{NaOH} ->[\Delta] \underset{(Ethene)}{CH2 = CH2} + NaBr + H2O}\]
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