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Question
What is the current I in the given circuit (Fig. )?
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Solution
In given circuit, two 2 ohm resistors in series are connected in parallel with another 2 ohm resistor;
Therefore equivalent resistance of the circuit,
R = [(2 + 2-1 + (2)-1]-1
R = `(1/4 + 1/2 = 3/4)`-1
R = `4/3`
I = `"V"/"R" = 3/(4//3) = 9/4` A = 225A
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