Advertisements
Advertisements
प्रश्न
What is the current I in the given circuit (Fig. )?

Advertisements
उत्तर
In given circuit, two 2 ohm resistors in series are connected in parallel with another 2 ohm resistor;
Therefore equivalent resistance of the circuit,
R = [(2 + 2-1 + (2)-1]-1
R = `(1/4 + 1/2 = 3/4)`-1
R = `4/3`
I = `"V"/"R" = 3/(4//3) = 9/4` A = 225A
APPEARS IN
संबंधित प्रश्न
Which particles are responsible for current in conductors?
An electric bulb is connected to a 220 V power supply line. If the bulb draws a current of 0.5 A, calculate the power of the bulb.
Two resistors A and B of resistance 4 Ω and 6 Ω respectively are connected in parallel. The combination is connected across a 6 volt battery of negligible resistance. Calculate: (i) the power supplied by the battery, (ii) the power dissipated in each resistor.
Name the physical quantity which is measured in kW.
Two resistors A and B of 4 Ω and 6 Ω respectively are connected in parallel. The combination is connected across a 6 volt battery of negligible resistance. Calculate the power supplied by the battery.
An electric bulb is marked 100 W, 230 V. What does this mean?
What is the order of current drawn by appliances connected to the ‘light circuit’ of a household?
An electric heater is rated 220 V, 550 W. What does this statement mean?
What is the commercial unit of electrical energy?
Two heaters A and B have power rating of 1 kW and 2 kW, respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is ______
