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Two metals A and B have specific heat capacities in the ratio 2:3. Which metal piece will have greater mass if the rise in temperature is the same for both metals?

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Question

Two metals A and B have specific heat capacities in the ratio 2:3. If they are supplied same amount of heat then

Which metal piece will have greater mass if the rise in temperature is the same for both metals?

Answer in Brief
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Solution

In this case, rise in temperature is same (Δ t) and masses are different.

So, for metal A,

Amount of heat (Q) = mA × 2 C × Δt;

and for metal B,

Amount of heat (Q) = mB × 3 C × Δt.

Now we can write, mA × 2C × Δt = mB × 3C × Δt.

Simplifying, mA = 1.5 mB.

Therefore, it can be said that metal A will have a greater mass than metal B.

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2021-2022 (March) Set 1

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