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Question
Two metals A and B have specific heat capacities in the ratio 2:3. If they are supplied same amount of heat then
Which metal piece will have greater mass if the rise in temperature is the same for both metals?
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Solution
In this case, rise in temperature is same (Δ t) and masses are different.
So, for metal A,
Amount of heat (Q) = mA × 2 C × Δt;
and for metal B,
Amount of heat (Q) = mB × 3 C × Δt.
Now we can write, mA × 2C × Δt = mB × 3C × Δt.
Simplifying, mA = 1.5 mB.
Therefore, it can be said that metal A will have a greater mass than metal B.
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