Question

Two metals A and B have specific heat capacities in the ratio 2:3. If they are supplied same amount of heat then

Which metal piece will have greater mass if the rise in temperature is the same for both metals?

Answer 1

In this case, rise in temperature is same (Δ t) and masses are different.

So, for metal A,

Amount of heat (Q) = m_A × 2 C × Δt;

and for metal B,

Amount of heat (Q) = m_B × 3 C × Δt.

Now we can write, m_A × 2C × Δt = m_B × 3C × Δt.

Simplifying, m_A = 1.5 m_B.

Therefore, it can be said that metal A will have a greater mass than metal B.