Question

Two metals A and B have specific heat capacities in the ratio 2 : 3. If they are supplied the same amount of heat then

Which metal piece will show a greater rise in temperature given their masses is the same?

Answer 1

It is given that, two metals A and B have specific heat capacities in the ratio 2 : 3. They are supplied the same amount of heat.

Assuming, the specific heat capacities of two metals A and B are 2 C and 3 C, respectively.

It is also given that, masses are same.

Let us take the heat amount is Q and masses are m.

So, for metal A,

Amount of heat (Q) = m × 2 C × Δt_A;

and for metal B,

Amount of heat (Q) = m × 3 C × Δt_B.

Now we can write, m × 2 C × Δt_A = m × 3C ×  Δt_B.

Simplifying, Δt_A = 1.5 Δt_B 

Therefore, it can be said that metal A will show a greater rise in temperature than metal B.