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प्रश्न
Calculate the amount of heat released when 5.0 g of water at 20°C is changed into ice at 0°C.
(Specific heat capacity of water = 4.2 J/g°C
Specific latent heat of fusion of ice = 336 J/g)
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उत्तर
5g water at 20° C \[\underrightarrow{mcθ}\] 5g water at 0° C \[\underrightarrow{mL}\] 5 g ice at 0°C.
∴ Amount of heat released = mcθ + mL
= 5 × 4.2 × (20° - 0°) + 5 × 336 = 21.0 × 20 + 1680
= 420 + 1680 = 2100 Joules
संबंधित प्रश्न
The temperature of 170 g of water at 50°C is lowered to 5°C by adding a certain amount of ice to it. Find the mass of ice added.
Given: Specific heat capacity of water = 4200 J kg-1 °C-1 and specific latent heat of ice = 336000 J kg-1.
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(a) the increase in yield of crops
(b) the decrease in sea levels
(c) the decrease in human deaths
(d) the increase in sea levels
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Write the approximate values of the specific latent heat of fusion of ice.
Numerical Problem.
What could be the final temperature of a mixture of 100 g of water at 90 °C and 600g of water at 20°C.
Explain why the specific heat capacity at constant pressure is greater than the specific heat capacity at constant volume.
A metal ball of heat capacity 50J/°C loses 2000 J of heat. By how much will its temperature fall?
