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प्रश्न
Calculate the amount of heat released when 5.0 g of water at 20°C is changed into ice at 0°C.
(Specific heat capacity of water = 4.2 J/g°C
Specific latent heat of fusion of ice = 336 J/g)
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उत्तर
5g water at 20° C \[\underrightarrow{mcθ}\] 5g water at 0° C \[\underrightarrow{mL}\] 5 g ice at 0°C.
∴ Amount of heat released = mcθ + mL
= 5 × 4.2 × (20° - 0°) + 5 × 336 = 21.0 × 20 + 1680
= 420 + 1680 = 2100 Joules
संबंधित प्रश्न
What do you understand by the following statements:
The specific heat capacity of lead is 130 Jkg-1K-1.
The temperature of 170 g of water at 50°C is lowered to 5°C by adding a certain amount of ice to it. Find the mass of ice added.
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The S.I. unit of specific heat capacity is ______.
(i) State whether the specific heat capacity of a substance remains the same when its state changes from solid to liquid.
(ii) Give one example to support your answer.
(b) 2000 J of heat energy is required to raise the temperature of 4 kg of a
metal by 3°c. Which expression gives the specific heat capacity of the metal?
Define heat capacity.
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How much heat energy is released when 5 g of water at 20° C changes to ice at 0° C?
[Specific heat capacity of water = 4.2 J g-1 ° C-1 Specific latent heat of fusion of ice = 336 J g-1]
Solve the following problem.
What is the specific heat of metal if 50 cal of heat is needed to raise 6 kg of the metal from 20°C to 62 °C?
