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Question
Two metals A and B have specific heat capacities in the ratio 2 : 3. If they are supplied the same amount of heat then
Which metal piece will show a greater rise in temperature given their masses is the same?
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Solution
It is given that, two metals A and B have specific heat capacities in the ratio 2 : 3. They are supplied the same amount of heat.
Assuming, the specific heat capacities of two metals A and B are 2 C and 3 C, respectively.
It is also given that, masses are same.
Let us take the heat amount is Q and masses are m.
So, for metal A,
Amount of heat (Q) = m × 2 C × ΔtA;
and for metal B,
Amount of heat (Q) = m × 3 C × ΔtB.
Now we can write, m × 2 C × ΔtA = m × 3C × ΔtB.
Simplifying, ΔtA = 1.5 ΔtB
Therefore, it can be said that metal A will show a greater rise in temperature than metal B.
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