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Question
Two metals A and B have specific heat capacities in the ratio 2:3. If they are supplied same amount of heat then
If the mass ratio of metal A and metal B is 3:5 then calculate the ratio in which their temperatures rise.
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Solution
In this case mass ratio, `"m"_"A"/"m"_"B" = 3/5`.
we can write, mA × 2 C × ΔtA = mB × 3 C × ΔtB.
Or, `(Delta"t"_"A")/(Delta"t"_"B") = (3"m"_"B")/(2"m"_"A")`
`= (3/2) xx ("m"_"B"/"m"_"A")`
`= (3/2) xx (5/3)`
`= 5/2`
Or, ΔtA = ΔtB = 5 : 2
Therefore, it can be said that for metal A and metal B, the ratio in which their temperatures rise is 5 : 2.
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