English

The value of ∫0π2log (4+3sinx4+3cosx) dx is ______. - Mathematics

Advertisements
Advertisements

Question

The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is ______.

Options

  • 2

  • `3/4`

  • 0

  • - 2

MCQ
Fill in the Blanks
Advertisements

Solution

The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is 0.

Explanation:

Let I `= int_0^(pi//2)  log  ((4 + 3 sin x)/(4 + 3 cos x))  "dx"`

Also, `I = int_0^(pi/2) log [(4+3 sin (pi/2 - x))/(4 + 3 cos (pi/2 - x))]  dx`

`[∵ int_0^a f (x) dx = int_0^a f (a - x) dx]`

⇒ ` I = int_0^(pi/2) log [(4+3 cos x)/(4+3 sin x)] dx`

⇒ `I = - int_0^(pi/2) log [(4+3sinx)/(4+3cosx)] dx`

⇒  I = -I

⇒  2I = 0

⇒  I = 0

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise 7.11 [Page 347]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.11 | Q 21 | Page 347

RELATED QUESTIONS

Evaluate : `int e^x[(sqrt(1-x^2)sin^-1x+1)/(sqrt(1-x^2))]dx`


Evaluate :`int_0^pi(xsinx)/(1+sinx)dx`


Evaluate: `int_(-a)^asqrt((a-x)/(a+x)) dx`


By using the properties of the definite integral, evaluate the integral:

`int_(-5)^5 | x + 2| dx`


By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


\[\int\limits_0^k \frac{1}{2 + 8 x^2} dx = \frac{\pi}{16},\] find the value of k.


\[\int_\pi^\frac{3\pi}{2} \sqrt{1 - \cos2x}dx\]

Evaluate : `int  "e"^(3"x")/("e"^(3"x") + 1)` dx


Evaluate the following integrals : `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7 - x))*dx`


Choose the correct alternative:

`int_(-9)^9 x^3/(4 - x^2)  "d"x` =


State whether the following statement is True or False:

`int_(-5)^5 x/(x^2 + 7)  "d"x` = 10


Evaluate `int_1^3 x^2*log x  "d"x`


`int (cos x + x sin x)/(x(x + cos x))`dx = ?


`int_-9^9 x^3/(4 - x^2)` dx = ______


`int_0^{pi/2} xsinx dx` = ______


`int_0^{pi/2} cos^2x  dx` = ______ 


The value of `int_1^3 dx/(x(1 + x^2))` is ______ 


`int_0^{1/sqrt2} (sin^-1x)/(1 - x^2)^{3/2} dx` = ______ 


`int_0^1 log(1/x - 1) "dx"` = ______.


`int_(-1)^1 (x + x^3)/(9 - x^2)  "d"x` = ______.


If `int_0^1 "e"^"t"/(1 + "t") "dt"` = a, then `int_0^1 "e"^"t"/(1 + "t")^2 "dt"` is equal to ______.


`int_(-2)^2 |x cos pix| "d"x` is equal to ______.


Evaluate the following:

`int_0^(pi/2)  "dx"/(("a"^2 cos^2x + "b"^2 sin^2 x)^2` (Hint: Divide Numerator and Denominator by cos4x)


Evaluate the following:

`int_(-pi/4)^(pi/4) log|sinx + cosx|"d"x`


`int_0^(pi/2) sqrt(1 - sin2x)  "d"x` is equal to ______.


If `int_0^"a" 1/(1 + 4x^2) "d"x = pi/8`, then a = ______.


`int (dx)/(e^x + e^(-x))` is equal to ______.


Evaluate: `int_(pi/6)^(pi/3) (dx)/(1 + sqrt(tanx)`


`int_0^1 1/(2x + 5) dx` = ______.


Evaluate: `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7) - x)dx`


`int_0^π(xsinx)/(1 + cos^2x)dx` equals ______.


If f(x) = `{{:(x^2",", "where"  0 ≤ x < 1),(sqrt(x)",", "when"  1 ≤ x < 2):}`, then `int_0^2f(x)dx` equals ______.


`int_0^(pi/4) (sec^2x)/((1 + tanx)(2 + tanx))dx` equals ______.


The value of the integral `int_0^1 x cot^-1(1 - x^2 + x^4)dx` is ______.


If `int_0^(2π) cos^2 x  dx = k int_0^(π/2) cos^2 x  dx`, then the value of k is ______.


Evaluate the following limit :

`lim_("x"->3)[sqrt("x"+6)/"x"]`


Evaluate the following definite intergral:

`int_1^2 (3x)/(9x^2 - 1) dx`


Evaluate the following definite intergral:

`int_1^3logx  dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×