हिंदी

The value of ∫0π2log (4+3sinx4+3cosx) dx is ______.

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प्रश्न

The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is ______.

विकल्प

  • 2

  • `3/4`

  • 0

  • - 2

MCQ
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उत्तर

The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is 0.

Explanation:

Let I `= int_0^(pi//2)  log  ((4 + 3 sin x)/(4 + 3 cos x))  "dx"`

Also, `I = int_0^(pi/2) log [(4+3 sin (pi/2 - x))/(4 + 3 cos (pi/2 - x))]  dx`

`[∵ int_0^a f (x) dx = int_0^a f (a - x) dx]`

⇒ ` I = int_0^(pi/2) log [(4+3 cos x)/(4+3 sin x)] dx`

⇒ `I = - int_0^(pi/2) log [(4+3sinx)/(4+3cosx)] dx`

⇒  I = -I

⇒  2I = 0

⇒  I = 0

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अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 21 | पृष्ठ ३४७

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