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∫-π2π2(x3+xcosx+tan5x+1)dx is ______.

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प्रश्न

`int_(-pi/2)^(pi/2) (x^3 + x cos x + tan^5 x + 1) dx ` is ______.

विकल्प

  • 0

  • 2

  • π

  • 1

MCQ
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उत्तर

`int_(-pi/2)^(pi/2) (x^3 + x cos x + tan^5 x + 1) dx ` is π.

Explanation:

Let `int_(-pi/2)^(pi/2) (x^3 + x  cos x + tan^5 x + 1)`  dx

`int_(-pi/2)^(pi/2) (x^3 + x  cos x + tan^5 x) dx + int_((-pi)/2)^(pi/2) 1* dx`

Because `(x^3 + x cos x + tan^5 x)` is an equivalent function.

Hence, `int_(-pi//2)^(pi//2) (x^3 + x  cos x + tan^5 x) dx = 0`

`=> I = 0 + [x]_(-pi/2)^(pi/2)`

`= pi/2 - (- pi/2)`

`= pi/2 + pi/2 = pi`

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अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 20 | पृष्ठ ३४७

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