हिंदी

By using the properties of the definite integral, evaluate the integral: ∫0π2 cos5 xdxsin5x+cos5x

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2)  (cos^5  xdx)/(sin^5 x + cos^5 x)`

योग
Advertisements

उत्तर

Let `I = int_0^(pi/2) (cos^5 x)/ (sin^5 x + cos ^5 x)  dx`     ....(i)

Also, `I = int_0^(pi/2) (cos^5 (pi/2 - x))/(sin^5 (pi/2 - x) + cos^5 (pi/2 - x)) dx`

`[∵ int_0^a f (x) dx = int_0^a f (a - x) dx]`

`= int_0^(pi/2) (sin^5 x)/ (cos^5x + sin^5 x)  dx`           ....(ii)

Adding (i) and (ii), we have

`2 I = int_0^(pi/2) (cos^5x)/(cos^5x + sin^5 x)  dx + int_0^(pi/2) (sin^5x)/ (cos^5 x + sin^5 x)  dx`

`= int_0^(pi/2) (cos^5 x + sin^5 x)/ (cos^5 x + sin^5 x) dx`

`= int_0^(pi/2) 1 dx = [x]_0^(pi/2) = pi/2`

Hence, `I = pi/4`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 4 | पृष्ठ ३४७

संबंधित प्रश्न

Evaluate : `int e^x[(sqrt(1-x^2)sin^-1x+1)/(sqrt(1-x^2))]dx`


By using the properties of the definite integral, evaluate the integral:

`int_2^8 |x - 5| dx`


By using the properties of the definite integral, evaluate the integral:

`int_((-pi)/2)^(pi/2) sin^2 x  dx`


Evaluate `int e^x [(cosx - sin x)/sin^2 x]dx`


Evaluate : \[\int(3x - 2) \sqrt{x^2 + x + 1}dx\] .


Evaluate : `int  "e"^(3"x")/("e"^(3"x") + 1)` dx


Evaluate :  `int 1/sqrt("x"^2 - 4"x" + 2) "dx"`


`int_(-7)^7 x^3/(x^2 + 7)  "d"x` = ______


Evaluate `int_0^1 x(1 - x)^5  "d"x`


`int_0^{pi/2} log(tanx)dx` = ______


`int_0^4 1/(1 + sqrtx)`dx = ______.


`int_"a"^"b" sqrtx/(sqrtx + sqrt("a" + "b" - x)) "dx"` = ______.


`int_(pi/18)^((4pi)/9) (2 sqrt(sin x))/(sqrt (sin x) + sqrt(cos x))` dx = ?


`int_3^9 x^3/((12 - x)^3 + x^3)` dx = ______ 


`int_0^1 "e"^(5logx) "d"x` = ______.


Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`


If `int_0^1 "e"^"t"/(1 + "t") "dt"` = a, then `int_0^1 "e"^"t"/(1 + "t")^2 "dt"` is equal to ______.


`int_(-2)^2 |x cos pix| "d"x` is equal to ______.


Evaluate the following:

`int_0^(pi/2)  "dx"/(("a"^2 cos^2x + "b"^2 sin^2 x)^2` (Hint: Divide Numerator and Denominator by cos4x)


`int_0^(pi/2) sqrt(1 - sin2x)  "d"x` is equal to ______.


`int_0^(pi/2)  cos x "e"^(sinx)  "d"x` is equal to ______.


`int_a^b f(x)dx` = ______.


If `int_0^1(sqrt(2x) - sqrt(2x - x^2))dx = int_0^1(1 - sqrt(1 - y^2) - y^2/2)dy + int_1^2(2 - y^2/2)dy` + I then I equal.


Let `int ((x^6 - 4)dx)/((x^6 + 2)^(1/4).x^4) = (ℓ(x^6 + 2)^m)/x^n + C`, then `n/(ℓm)` is equal to ______.


The value of the integral `int_0^sqrt(2)([sqrt(2 - x^2)] + 2x)dx` (where [.] denotes greatest integer function) is ______.


If f(x) = `{{:(x^2",", "where"  0 ≤ x < 1),(sqrt(x)",", "when"  1 ≤ x < 2):}`, then `int_0^2f(x)dx` equals ______.


The value of the integral `int_0^1 x cot^-1(1 - x^2 + x^4)dx` is ______.


Evaluate: `int_0^π 1/(5 + 4 cos x)dx`


If `int_0^K dx/(2 + 18x^2) = π/24`, then the value of K is ______.


`int_-1^1 (17x^5 - x^4 + 29x^3 - 31x + 1)/(x^2 + 1) dx` is equal to ______.


Evaluate `int_-1^1 |x^4 - x|dx`.


The value of `int_0^(π/4) (sin 2x)dx` is ______.


For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.


Evaluate the following integral:

`int_0^1 x(1 - 5)^5`dx


 `int_-9^9 x^3/(4-x^2) dx` =______


Evaluate the following definite integral:

`int_1^3 log x  dx`


Solve the following.

`int_0^1e^(x^2)x^3 dx`


Evaluate the following integral:

`int_0^1 x (1 - x)^5 dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


The value of \[\int_{-1}^{1}\left(\sqrt{1+x+x^{2}}-\sqrt{1-x+x^{2}}\right)\mathrm{d}x\] is


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×