हिंदी

By using the properties of the definite integral, evaluate the integral: ∫0π2sin32xsin32x+cos32xdx - Mathematics

Advertisements
Advertisements

प्रश्न

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`

योग
Advertisements

उत्तर

Let I = `int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`

I = `int_0^(pi/2) cos^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`

`2I = int_0^(pi/2) (sin^(3/2)x/(sin^(3/2)x+cos^(3/2) x)+cos^(3/2)x/(sin^(3/2)x + cos^(3/2)x)) dx`

Simplify the numerator:

`(sin^(3/2)x+cos^(3/2) x)/(sin^(3/2)x+cos^(3/2)) = 1`

`2I = int_0^(pi/2) 1 dx`

`int_0^(pi/2) 1 dx = [x]_0^(pi/2)=pi/2 - 0 = pi/2`

`2I = pi/2`

`I=pi/4`

`pi/4`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise 7.11 [पृष्ठ ३४७]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.11 | Q 3 | पृष्ठ ३४७

संबंधित प्रश्न

If `int_0^alpha3x^2dx=8` then the value of α is :

(a) 0

(b) -2

(c) 2 

(d) ±2


Evaluate : \[\int(3x - 2) \sqrt{x^2 + x + 1}dx\] .


Evaluate`int (1)/(x(3+log x))dx` 


Find `dy/dx, if y = cos^-1 ( sin 5x)`


Prove that `int_0^"a" "f" ("x") "dx" = int_0^"a" "f" ("a" - "x") "d x",` hence evaluate `int_0^pi ("x" sin "x")/(1 + cos^2 "x") "dx"`


Choose the correct alternative:

`int_(-9)^9 x^3/(4 - x^2)  "d"x` =


`int_0^1 "e"^(2x) "d"x` = ______


`int_0^1 ((x^2 - 2)/(x^2 + 1))`dx = ?


`int_3^9 x^3/((12 - x)^3 + x^3)` dx = ______ 


`int_-2^1 dx/(x^2 + 4x + 13)` = ______


`int_{pi/6}^{pi/3} sin^2x dx` = ______ 


`int_0^1 "dx"/(sqrt(1 + x) - sqrtx)` = ?


`int_0^1 log(1/x - 1) "dx"` = ______.


`int_0^{pi/2} (cos2x)/(cosx + sinx)dx` = ______


`int_0^pi x*sin x*cos^4x  "d"x` = ______.


Evaluate `int_0^(pi/2) (tan^7x)/(cot^7x + tan^7x) "d"x`


`int (dx)/(e^x + e^(-x))` is equal to ______.


If `int_a^b x^3 dx` = 0, then `(x^4/square)_a^b` = 0

⇒ `1/4 (square - square)` = 0

⇒ b4 – `square` = 0

⇒ (b2 – a2)(`square` + `square`) = 0

⇒ b2 – `square` = 0 as a2 + b2 ≠ 0

⇒ b = ± `square`


`int_a^b f(x)dx` = ______.


If `intxf(x)dx = (f(x))/2` then f(x) = ex.


`int_0^5 cos(π(x - [x/2]))dx` where [t] denotes greatest integer less than or equal to t, is equal to ______.


The value of the integral `int_(-1)^1log_e(sqrt(1 - x) + sqrt(1 + x))dx` is equal to ______.


`int_0^1|3x - 1|dx` equals ______.


The value of the integral `int_0^sqrt(2)([sqrt(2 - x^2)] + 2x)dx` (where [.] denotes greatest integer function) is ______.


Let f be continuous periodic function with period 3, such that `int_0^3f(x)dx` = 1. Then the value of `int_-4^8f(2x)dx` is ______.


`int_0^(pi/4) (sec^2x)/((1 + tanx)(2 + tanx))dx` equals ______.


The value of the integral `int_0^1 x cot^-1(1 - x^2 + x^4)dx` is ______.


What is `int_0^(π/2)` sin 2x ℓ n (cot x) dx equal to ?


With the usual notation `int_1^2 ([x^2] - [x]^2)dx` is equal to ______.


If `int_0^K dx/(2 + 18x^2) = π/24`, then the value of K is ______.


`int_0^(π/2)((root(n)(secx))/(root(n)(secx + root(n)("cosec"  x))))dx` is equal to ______.


If `int_0^(2π) cos^2 x  dx = k int_0^(π/2) cos^2 x  dx`, then the value of k is ______.


The value of `int_0^(π/4) (sin 2x)dx` is ______.


Evaluate : `int_-1^1 log ((2 - x)/(2 + x))dx`.


Solve the following.

`int_0^1 e^(x^2) x^3dx`


Evaluate the following integrals:

`int_-9^9 x^3/(4 - x^3 ) dx`


Solve the following.

`int_2^3x/((x+2)(x+3))dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×