Advertisements
Advertisements
प्रश्न
`int_-1^1 |x - 2|/(x - 2) dx`, x ≠ 2 is equal to ______.
विकल्प
1
– 1
2
– 2
Advertisements
उत्तर
`int_-1^1 |x - 2|/(x - 2) dx`, x ≠ 2 is equal to – 2.
Explanation:
`int_-1^1 |x - 2|/(x - 2) dx`; x ≠ 2 = `[-x]_-1^1`
= – [1 + 1]
= – 2.
संबंधित प्रश्न
By using the properties of the definite integral, evaluate the integral:
`int_0^(pi/2) cos^2 x dx`
By using the properties of the definite integral, evaluate the integral:
`int_0^(pi/4) log (1+ tan x) dx`
Evaluate `int e^x [(cosx - sin x)/sin^2 x]dx`
Evaluate : `int _0^(pi/2) "sin"^ 2 "x" "dx"`
Evaluate : `int "e"^(3"x")/("e"^(3"x") + 1)` dx
Evaluate : ∫ log (1 + x2) dx
`int (cos x + x sin x)/(x(x + cos x))`dx = ?
`int_0^(pi"/"4)` log(1 + tanθ) dθ = ______
`int_0^{pi/4} (sin2x)/(sin^4x + cos^4x)dx` = ____________
`int_(pi/4)^(pi/2) sqrt(1-sin 2x) dx =` ______.
The value of `int_2^7 (sqrtx)/(sqrt(9 - x) + sqrtx)dx` is ______
Evaluate `int_0^(pi/2) (tan^7x)/(cot^7x + tan^7x) "d"x`
`int_(-1)^1 (x^3 + |x| + 1)/(x^2 + 2|x| + 1) "d"x` is equal to ______.
`int_0^(2"a") "f"(x) "d"x = 2int_0^"a" "f"(x) "d"x`, if f(2a – x) = ______.
`int_0^(pi/2) (sin^"n" x"d"x)/(sin^"n" x + cos^"n" x)` = ______.
Evaluate the following:
`int_0^(pi/2) "dx"/(("a"^2 cos^2x + "b"^2 sin^2 x)^2` (Hint: Divide Numerator and Denominator by cos4x)
`int_0^(pi/2) cos x "e"^(sinx) "d"x` is equal to ______.
If `int_a^b x^3 dx` = 0, then `(x^4/square)_a^b` = 0
⇒ `1/4 (square - square)` = 0
⇒ b4 – `square` = 0
⇒ (b2 – a2)(`square` + `square`) = 0
⇒ b2 – `square` = 0 as a2 + b2 ≠ 0
⇒ b = ± `square`
If `int_0^1(sqrt(2x) - sqrt(2x - x^2))dx = int_0^1(1 - sqrt(1 - y^2) - y^2/2)dy + int_1^2(2 - y^2/2)dy` + I then I equal.
Evaluate: `int_0^π 1/(5 + 4 cos x)dx`
Evaluate: `int_0^π x/(1 + sinx)dx`.
Evaluate: `int_0^(π/4) log(1 + tanx)dx`.
Evaluate the following integral:
`int_0^1 x(1-x)^5 dx`
Evaluate the following integral:
`int_-9^9 x^3/(4 - x^2) dx`
Evaluate the following integral:
`int_-9^9 x^3 / (4 - x^2) dx`
Solve.
`int_0^1e^(x^2)x^3dx`
Evaluate the following integral:
`int_-9^9x^3/(4-x^2)dx`
