English

∫-11|x-2|x-2dx, x ≠ 2 is equal to ______.

Advertisements
Advertisements

Question

`int_-1^1 |x - 2|/(x - 2) dx`, x ≠ 2 is equal to ______.

Options

  • 1

  • – 1

  • 2

  • – 2

MCQ
Fill in the Blanks
Advertisements

Solution

`int_-1^1 |x - 2|/(x - 2) dx`, x ≠ 2 is equal to – 2.

Explanation:

`int_-1^1 |x - 2|/(x - 2) dx`; x ≠ 2 = `[-x]_-1^1`

= – [1 + 1]

= – 2.

shaalaa.com
  Is there an error in this question or solution?
2022-2023 (March) Delhi Set 1

RELATED QUESTIONS

 
 

Evaluate `int_(-2)^2x^2/(1+5^x)dx`

 
 

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) sin^(3/2)x/(sin^(3/2)x + cos^(3/2) x) dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^4 |x - 1| dx`


The value of `int_0^(pi/2) log  ((4+ 3sinx)/(4+3cosx))` dx is ______.


`∫_4^9 1/sqrtxdx=`_____

(A) 1

(B) –2

(C) 2

(D) –1


Evaluate `int_0^(pi/2) cos^2x/(1+ sinx cosx) dx`


Evaluate :  `int 1/sqrt("x"^2 - 4"x" + 2) "dx"`


Evaluate: `int_0^pi ("x"sin "x")/(1+ 3cos^2 "x") d"x"`.


Evaluate the following integrals : `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7 - x))*dx`


`int_"a"^"b" "f"(x)  "d"x` = ______


`int_0^1 (1 - x)^5`dx = ______.


`int_{pi/6}^{pi/3} sin^2x dx` = ______ 


`int_-1^1x^2/(1+x^2)  dx=` ______.


`int_0^(pi/2) 1/(1 + cosx) "d"x` = ______.


`int_0^pi x sin^2x dx` = ______ 


Evaluate `int_(-1)^2 "f"(x)  "d"x`, where f(x) = |x + 1| + |x| + |x – 1|


Evaluate: `int_1^3 sqrt(x)/(sqrt(x) + sqrt(4) - x) dx`


Evaluate: `int_((-π)/2)^(π/2) (sin|x| + cos|x|)dx`


If `intxf(x)dx = (f(x))/2` then f(x) = ex.


`int_-1^1 (17x^5 - x^4 + 29x^3 - 31x + 1)/(x^2 + 1) dx` is equal to ______.


Evaluate `int_0^(π//4) log (1 + tanx)dx`.


For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.


Evaluate: `int_0^(π/4) log(1 + tanx)dx`.


`int_1^2 x logx  dx`= ______


Solve the following.

`int_2^3x/((x+2)(x+3))dx`


Evaluate the following definite integral:

`int_-2^3(1)/(x + 5)  dx`


\[\int_{-2}^{2}\left|x^{2}-x-2\right|\mathrm{d}x=\]


`int_0^(pi/4) (cos^2 x)/(cos^2 x + 4 sin^2 x) dx` =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×