English

By using the properties of the definite integral, evaluate the integral: ∫01x(1-x)ndx

Advertisements
Advertisements

Question

By using the properties of the definite integral, evaluate the integral:

`int_0^1 x(1-x)^n dx`

Sum
Advertisements

Solution

`int_0^1  (1 - x) [1 - (1 - x)^n] dx        ...[because int_0^a  f(x) dx = int_0^a  f(a - x)  dx]`

Hence,  `I = int_0^1 (1 - x).x^n  dx`

`I = int_0^1  (x^n - x^(n + 1))  dx`

`= ([x^(n + 1)]_0^1)/(n + 1) - ([n^(n + 2)]_0^1)/(n + 2)`

`= 1/(n + 2) - 1/(n + 2)`

`= (n + 2 - n - 1)/((n + 1)(n + 2))`

`= 1/((n + 1)(n + 2))`

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise 7.11 [Page 347]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 7 Integrals
Exercise 7.11 | Q 7 | Page 347

RELATED QUESTIONS

Prove that: `int_0^(2a)f(x)dx=int_0^af(x)dx+int_0^af(2a-x)dx`


If `int_0^alpha3x^2dx=8` then the value of α is :

(a) 0

(b) -2

(c) 2 

(d) ±2


 
 

Evaluate : `intlogx/(1+logx)^2dx`

 
 

By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) cos^2 x dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^pi (x  dx)/(1+ sin x)`


By using the properties of the definite integral, evaluate the integral:

`int_0^a  sqrtx/(sqrtx + sqrt(a-x))   dx`


`∫_4^9 1/sqrtxdx=`_____

(A) 1

(B) –2

(C) 2

(D) –1


\[\int\limits_0^k \frac{1}{2 + 8 x^2} dx = \frac{\pi}{16},\] find the value of k.


\[\int_\pi^\frac{3\pi}{2} \sqrt{1 - \cos2x}dx\]

Evaluate :  `int 1/sqrt("x"^2 - 4"x" + 2) "dx"`


Find : `int_  (2"x"+1)/(("x"^2+1)("x"^2+4))d"x"`.


Evaluate the following integrals : `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7 - x))*dx`


`int_2^4 x/(x^2 + 1)  "d"x` = ______


The c.d.f, F(x) associated with p.d.f. f(x) = 3(1- 2x2). If 0 < x < 1 is k`(x - (2x^3)/"k")`, then value of k is ______.


If `int_0^"a" sqrt("a - x"/x) "dx" = "K"/2`, then K = ______.


`int_(pi/18)^((4pi)/9) (2 sqrt(sin x))/(sqrt (sin x) + sqrt(cos x))` dx = ?


`int_-1^1x^2/(1+x^2)  dx=` ______.


Find `int_0^(pi/4) sqrt(1 + sin 2x) "d"x`


Evaluate:

`int_2^8 (sqrt(10 - "x"))/(sqrt"x" + sqrt(10 - "x")) "dx"`


The value of `int_0^1 tan^-1 ((2x - 1)/(1 + x - x^2))  dx` is


`int_0^1 1/(2x + 5) dx` = ______.


Evaluate: `int_2^5 sqrt(x)/(sqrt(x) + sqrt(7) - x)dx`


Let `int ((x^6 - 4)dx)/((x^6 + 2)^(1/4).x^4) = (ℓ(x^6 + 2)^m)/x^n + C`, then `n/(ℓm)` is equal to ______.


`int_0^(pi/4) (sec^2x)/((1 + tanx)(2 + tanx))dx` equals ______.


`int_0^(π/4) x. sec^2 x  dx` = ______.


If `int_0^(π/2) log cos x  dx = π/2 log(1/2)`, then `int_0^(π/2) log sec dx` = ______.


Evaluate `int_-1^1 |x^4 - x|dx`.


Assertion (A): `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x))dx` = 3.

Reason (R): `int_a^b f(x) dx = int_a^b f(a + b - x) dx`.


For any integer n, the value of `int_-π^π e^(cos^2x) sin^3 (2n + 1)x  dx` is ______.


 `int_-9^9 x^3/(4-x^2) dx` =______


Solve the following.

`int_0^1e^(x^2)x^3 dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


`∫_0^(π/2) (sqrttan x + sqrtcot x)dx` = ______.


What is the value of a definite integral when its upper and lower limits are equal?


Which expression equals \[\int_{a}^{b} f(x)\,dx\] by \[P_3\] : The "King's Rule"?


If \[I=\int_{\frac{\pi}{6}}^{\frac{\pi}{3}}\frac{dx}{1+\sqrt{\tan x}}\], what is the value of \[I\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×