Question

Evaluate:

`int_0^1 |2x + 1|dx`

Answer 1

`int_0^1 |2x + 1|dx`

= `int_0^1 2x + 1 dx`    ...`{{:("For"  0 < x < 1),(2x + 1 > 0),(∴ |2x + 1| = 2x + 1):}`

= `[2 x^2/2 + x]_0^1`

= `[x^2 + x]_0^1`

= (1 + 1) – (0 + 0)

= 2