English

Ed∫0π2 cosxesinx dx is equal to ______. - Mathematics

Advertisements
Advertisements

Question

`int_0^(pi/2)  cos x "e"^(sinx)  "d"x` is equal to ______.

Fill in the Blanks
Advertisements

Solution

`int_0^(pi/2)  cos x "e"^(sinx)  "d"x` is equal to e – 1.

Explanation:

Let I = `int_0^(pi/2)  cos x "e"^(sinx)  "d"x` 

Put sin x = t

⇒ cos x "d"x` = dt

∴ I = `int_0^1 "e"^"t"  "dt"`

= `["e"^"t"]_0^1`

= `"e"^1 - "e"^0`

= e – 1

shaalaa.com
  Is there an error in this question or solution?
Chapter 7: Integrals - Exercise [Page 169]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 12
Chapter 7 Integrals
Exercise | Q 59 | Page 169

RELATED QUESTIONS

Evaluate: `int_(-a)^asqrt((a-x)/(a+x)) dx`


By using the properties of the definite integral, evaluate the integral:

`int_(-5)^5 | x + 2| dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/4) log (1+ tan x) dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^2 xsqrt(2 -x)dx`


By using the properties of the definite integral, evaluate the integral:

`int_((-pi)/2)^(pi/2) sin^2 x  dx`


By using the properties of the definite integral, evaluate the integral:

`int_0^(pi/2) (sin x - cos x)/(1+sinx cos x) dx`


`∫_4^9 1/sqrtxdx=`_____

(A) 1

(B) –2

(C) 2

(D) –1


\[\int\limits_0^a 3 x^2 dx = 8,\] find the value of a.


Evaluate : \[\int(3x - 2) \sqrt{x^2 + x + 1}dx\] .


Evaluate : `int  "e"^(3"x")/("e"^(3"x") + 1)` dx


Prove that `int_0^"a" "f" ("x") "dx" = int_0^"a" "f" ("a" - "x") "d x",` hence evaluate `int_0^pi ("x" sin "x")/(1 + cos^2 "x") "dx"`


`int_"a"^"b" "f"(x)  "d"x` = ______


`int_2^7 sqrt(x)/(sqrt(x) + sqrt(9 - x))  dx` = ______.


Evaluate `int_1^3 x^2*log x  "d"x`


`int_-2^1 dx/(x^2 + 4x + 13)` = ______


`int_0^{1/sqrt2} (sin^-1x)/(1 - x^2)^{3/2} dx` = ______ 


`int_0^1 "dx"/(sqrt(1 + x) - sqrtx)` = ?


`int_(pi/4)^(pi/2) sqrt(1-sin 2x)  dx =` ______.


The value of `int_2^7 (sqrtx)/(sqrt(9 - x) + sqrtx)dx` is ______ 


Find `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x)) "d"x`


`int_(-1)^1 (x^3 + |x| + 1)/(x^2 + 2|x| + 1) "d"x` is equal to ______.


`int_(-2)^2 |x cos pix| "d"x` is equal to ______.


If `int_0^"a" 1/(1 + 4x^2) "d"x = pi/8`, then a = ______.


`int_0^5 cos(π(x - [x/2]))dx` where [t] denotes greatest integer less than or equal to t, is equal to ______.


If `int_(-a)^a(|x| + |x - 2|)dx` = 22, (a > 2) and [x] denotes the greatest integer ≤ x, then `int_a^(-a)(x + [x])dx` is equal to ______.


The value of the integral `int_(-1)^1log_e(sqrt(1 - x) + sqrt(1 + x))dx` is equal to ______.


If f(x) = `{{:(x^2",", "where"  0 ≤ x < 1),(sqrt(x)",", "when"  1 ≤ x < 2):}`, then `int_0^2f(x)dx` equals ______.


Evaluate: `int_0^π 1/(5 + 4 cos x)dx`


`int_(π/3)^(π/2) x sin(π[x] - x)dx` is equal to ______.


If `int_0^K dx/(2 + 18x^2) = π/24`, then the value of K is ______.


If `int_0^(π/2) log cos x  dx = π/2 log(1/2)`, then `int_0^(π/2) log sec dx` = ______.


`int_((-π)/2)^(π/2) log((2 - sinx)/(2 + sinx))` is equal to ______.


Evaluate `int_0^(π//4) log (1 + tanx)dx`.


Evaluate: `int_0^π x/(1 + sinx)dx`.


Solve the following.

`int_0^1e^(x^2)x^3 dx`


Evaluate the following integral:

`int_0^1 x(1 - x)^5 dx`


Solve.

`int_0^1e^(x^2)x^3dx`


Solve the following.

`int_0^1e^(x^2)x^3dx`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×