मराठी

Ed∫0π2 cosxesinx dx is equal to ______.

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प्रश्न

`int_0^(pi/2)  cos x "e"^(sinx)  "d"x` is equal to ______.

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उत्तर

`int_0^(pi/2)  cos x "e"^(sinx)  "d"x` is equal to e – 1.

Explanation:

Let I = `int_0^(pi/2)  cos x "e"^(sinx)  "d"x` 

Put sin x = t

⇒ cos x "d"x` = dt

∴ I = `int_0^1 "e"^"t"  "dt"`

= `["e"^"t"]_0^1`

= `"e"^1 - "e"^0`

= e – 1

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पाठ 7: Integrals - Exercise [पृष्ठ १६९]

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