मराठी

Ed∫x+3(x+4)2ex dx = ______.

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प्रश्न

`int (x + 3)/(x + 4)^2 "e"^x  "d"x` = ______.

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उत्तर

`int (x + 3)/(x + 4)^2 "e"^x  "d"x` = `"e"^x/(x + 4) + "C"`.

Explanation:

Let I = `int (x + 3)/(x + 4)^2 * "e"^x  "d"x`

= `int (x + 4 - 1)/(x + 4)^2 * "e"^x  "d"x`

= `int [(x + 4)/(x + 4)^2 - 1/(x + 4)^2]"e"^x  "d"x`

= `int [1/(x + 4) - 1/(x + 4)^2]"e"^x  "d"x`

Put `1/(x + 4)` = t

⇒ `- 1/(x + 4)^2  "d"x` = dt

Let f(x) = `1/(x + 4)`

∴ f'(x) = `- 1/(x + 4)^2`

Using `int "e"^x ["f"(x) + "f'"(x)]"d"x = "e"^x "f"(x) + "C"`

∴ I = `"e"^x * 1/(x + 4) + "C"`.

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पाठ 7: Integrals - Exercise [पृष्ठ १६९]

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