Advertisements
Advertisements
प्रश्न
If \[\left[ \cdot \right] and \left\{ \cdot \right\}\] denote respectively the greatest integer and fractional part functions respectively, evaluate the following integrals:
Advertisements
उत्तर
\[\text{We have}, \]
\[I = \int\limits_0^{\pi/4} \sin \left\{ x \right\} dx\]
\[\text{We know that}, \]
\[\left\{ x \right\} = x\text{, when }0 < x < \frac{\pi}{4} ..............\left(\text{As }\pi = 3 . 14 \Rightarrow \frac{\pi}{4} = 0 . 785 < 1 \right)\]
\[ \therefore I = \int\limits_0^{\pi/4} \sin x\ dx\]
\[ = \left[ - \cos x \right]_0^\frac{\pi}{4} \]
\[ = - \left( \cos \frac{\pi}{4} - \cos 0 \right)\]
\[ = \cos 0 - \cos \frac{\pi}{4}\]
\[ = 1 - \frac{1}{\sqrt{2}}\]
\[ = \frac{\sqrt{2} - 1}{\sqrt{2}}\]
APPEARS IN
संबंधित प्रश्न
\[\int\limits_{\pi/4}^{\pi/2} \cot x\ dx\]
The value of the integral \[\int\limits_0^{\pi/2} \frac{\sqrt{\cos x}}{\sqrt{\cos x} + \sqrt{\sin x}} dx\] is
The value of \[\int\limits_0^{\pi/2} \log\left( \frac{4 + 3 \sin x}{4 + 3 \cos x} \right) dx\] is
The value of \[\int\limits_{- \pi/2}^{\pi/2} \left( x^3 + x \cos x + \tan^5 x + 1 \right) dx, \] is
`int_0^(2a)f(x)dx`
\[\int\limits_0^1 \cos^{- 1} x dx\]
\[\int\limits_0^{\pi/4} e^x \sin x dx\]
\[\int\limits_{- a}^a \frac{x e^{x^2}}{1 + x^2} dx\]
\[\int\limits_0^\pi \frac{x \tan x}{\sec x + \tan x} dx\]
\[\int\limits_2^3 \frac{\sqrt{x}}{\sqrt{5 - x} + \sqrt{x}} dx\]
\[\int\limits_1^3 \left( 2 x^2 + 5x \right) dx\]
Evaluate the following using properties of definite integral:
`int_(-1)^1 log ((2 - x)/(2 + x)) "d"x`
Evaluate the following using properties of definite integral:
`int_0^(i/2) (sin^7x)/(sin^7x + cos^7x) "d"x`
Choose the correct alternative:
`int_0^1 (2x + 1) "d"x` is
Choose the correct alternative:
`int_0^oo "e"^(-2x) "d"x` is
Evaluate `int (x^2"d"x)/(x^4 + x^2 - 2)`
If x = `int_0^y "dt"/sqrt(1 + 9"t"^2)` and `("d"^2y)/("d"x^2)` = ay, then a equal to ______.
Which integral has lower and upper limits?
Using \[F\] as an antiderivative, how is \[\int_{a}^{b}f(x)\,dx\] evaluated?
