मराठी

∞ ∫ 0 1 a 2 + B 2 X 2 D X

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प्रश्न

\[\int\limits_0^\infty \frac{1}{a^2 + b^2 x^2} dx\]
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उत्तर

\[Let\ I = \int_0^\infty \frac{1}{a^2 + b^2 x^2} d x\ . Then, \]
\[I = \frac{1}{a^2} \int_0^\infty \frac{1}{1 + \frac{b^2 x^2}{a^2}} d x\]
\[ \Rightarrow I = \frac{1}{a^2} \int_0^\infty \frac{1}{1 + \left( \frac{bx}{a} \right)^2} d x\]
\[ \Rightarrow I = \frac{a}{b a^2} \left[ \tan^{- 1} \left( \frac{bx}{a} \right) \right]_0^\infty \]
\[ \Rightarrow I = \frac{1}{ab}\left( \tan^{- 1} \infty - \tan^{- 1} 0 \right)\]
\[ \Rightarrow I = \frac{\pi}{2ab}\]

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पाठ 19: Definite Integrals - Exercise 20.1 [पृष्ठ १६]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 19 Definite Integrals
Exercise 20.1 | Q 6 | पृष्ठ १६

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