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प्रश्न
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उत्तर
\[\int_0^\frac{\pi}{2} \cos^2 x\ d x\]
\[ = \int_0^\frac{\pi}{2} \frac{1 + \cos2x}{2} dx\]
\[ = \frac{1}{2} \int_0^\frac{\pi}{2} \left( 1 + \cos2x \right) dx\]
\[ = \frac{1}{2} \left[ x + \frac{\sin2x}{2} \right]_0^\frac{\pi}{2} \]
\[ = \frac{1}{2}\left[ \frac{\pi}{2} + 0 \right]\]
\[ = \frac{\pi}{4}\]
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