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प्रश्न

\[\int\limits_{- 2}^1 \frac{\left| x \right|}{x} dx .\]
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उत्तर

\[Let\, I = \int_{- 2}^1 \frac{\left| x \right|}{x} d x\]

\[\text{We have}, \]

\[\left| x \right| = \begin{cases}x&,& 0 \leq x \leq 1\\ - x&,& - 2 \leq x < 0\end{cases}\]

\[ \therefore \frac{\left| x \right|}{x} = \begin{cases}1&,& 0 \leq x \leq 1\\ - 1&,& - 2 \leq x < 0\end{cases}\]

\[\text{Therefore}, \]

\[I = \int_{- 2}^0 - 1dx + \int_0^1 1 dx\]

\[ = - \left[ x \right]_{- 2}^0 + \left[ x \right]_0^1 \]

\[ = 0 - 2 + 1 - 0\]

\[ = - 1\]

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Definite Integrals
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पाठ 20: Definite Integrals - Very Short Answers [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
Very Short Answers | Q 9 | पृष्ठ ११५

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