मराठी

Π ∫ 0 5 ( 5 − 4 Cos θ ) 1 / 4 Sin θ D θ

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प्रश्न

\[\int\limits_0^\pi 5 \left( 5 - 4 \cos \theta \right)^{1/4} \sin \theta\ d \theta\]
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उत्तर

\[Let\ I = \int_0^\pi 5 \left( 5 - 4\cos \theta \right)^\frac{1}{4} \sin \theta\ d \theta . \]

\[Let\left( 5 - 4 \cos \theta \right) = t . Then, 4 \sin \theta\ d\theta = dt\]

\[When\ \theta = 0, t = 1\ and\ \theta = \pi, t = 9\]

\[ \therefore I = \frac{5}{4} \int_1^9 t^\frac{1}{4} dt\]

\[ \Rightarrow I = \frac{5}{4} \left[ \frac{4 t^\frac{5}{4}}{5} \right]_1^9 \]

\[ \Rightarrow I = \left( 9\sqrt{3} - 1 \right)\]

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पाठ 19: Definite Integrals - Exercise 20.2 [पृष्ठ ३९]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 19 Definite Integrals
Exercise 20.2 | Q 42 | पृष्ठ ३९

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