मराठी

Π / 3 ∫ π / 6 1 Sin 2 X D X is Equal to , Loge 3 ,Log E √ 3,1 2 Log ( − 1 ), Log (−1)

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प्रश्न

\[\int\limits_{\pi/6}^{\pi/3} \frac{1}{\sin 2x} dx\]  is equal to

पर्याय

  •  loge 3

  • \[\log_e \sqrt{3}\]
  • \[\frac{1}{2}\log\left( - 1 \right)\]
  •  log (−1)

     
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उत्तर

\[\log_e \sqrt{3}\]

\[\int_\frac{\pi}{6}^\frac{\pi}{3} \frac{1}{\sin2x} d x\]
\[ = \int_\frac{\pi}{6}^\frac{\pi}{3} \ cosec2x\ dx\]
\[ = \frac{1}{2} \int_\frac{\pi}{6}^\frac{\pi}{3} 2\ cosec2x\ dx\]
\[ = \frac{- 1}{2} \left[ \log\left( \ cosec\ 2x\ + \cot2x \right) \right]_\frac{\pi}{6}^\frac{\pi}{3} \]
\[ = \frac{- 1}{2}\left[ - 2\log\sqrt{3} \right]\]
\[ = \log\sqrt{3}\]

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पाठ 19: Definite Integrals - MCQ [पृष्ठ ११९]

APPEARS IN

आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
पाठ 19 Definite Integrals
MCQ | Q 24 | पृष्ठ ११९

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