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Π / 4 ∫ 0 Tan 4 X D X - Mathematics

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प्रश्न

\[\int\limits_0^{\pi/4} \tan^4 x dx\]

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उत्तर

\[\int_0^\frac{\pi}{4} \tan^4 x d x\]
\[ = \int_0^\frac{\pi}{4} \tan^2 x\left( se c^2 x - 1 \right) d x\]
\[ = \int_0^\frac{\pi}{4} \tan^2 x se c^2 x dx - \int_0^\frac{\pi}{4} \tan^2 x dx\]
\[ = \left[ \frac{\tan^3 x}{3} \right]_0^\frac{\pi}{4} - \left[ \tan x - x \right]_0^\frac{\pi}{4} \]
\[ = \frac{1}{3} - 1 + \frac{\pi}{4}\]
\[ = \frac{\pi}{4} - \frac{2}{3}\]

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Definite Integrals
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पाठ 20: Definite Integrals - Revision Exercise [पृष्ठ १२२]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
Revision Exercise | Q 28 | पृष्ठ १२२

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