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Π / 2 ∫ 0 X Sin X D X - Mathematics

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प्रश्न

\[\int\limits_0^{\pi/2} x \sin x\ dx\]  is equal to

पर्याय

  •  π/4

  •  π/2

  • π

  • 1

MCQ
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उत्तर

1

\[\text{We have}, \]

\[ I = \int_0^\frac{\pi}{2} x \sin x\ d x \]

\[ = \left[ - x \cos x \right]_0^\frac{\pi}{2} - \int_0^\frac{\pi}{2} 1\left( - \cos x \right) d x\]

\[ = \left[ - x \cos x \right]_0^\frac{\pi}{2} + \int_0^\frac{\pi}{2} \cos x\ d x\]

\[ = - \left[ x \cos x \right]_0^\frac{\pi}{2} + \left[ \sin x \right]_0^\frac{\pi}{2} \]

\[ = - \left[ 0 - 0 \right] + \left[ 1 - 0 \right]\]

\[ = 1\]

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Definite Integrals
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पाठ 20: Definite Integrals - MCQ [पृष्ठ १२०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
MCQ | Q 34 | पृष्ठ १२०

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