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The Value of π / 2 ∫ 0 Log ( 4 + 3 Sin X 4 + 3 Cos X ) D X Is,2,3 4,0,−2 - Mathematics

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प्रश्न

The value of \[\int\limits_0^{\pi/2} \log\left( \frac{4 + 3 \sin x}{4 + 3 \cos x} \right) dx\] is 

 

पर्याय

  • 2

  • \[\frac{3}{4}\]
  • 0

  • −2

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उत्तर

0

\[Let\ I = \int_0^\frac{\pi}{2} \log\left( \frac{4 + 3\sin x}{4 + 3\cos x} \right) d x ............(1)\]
\[ = \int_0^\frac{\pi}{2} \log\left[ \frac{4 + 3\sin\left( \frac{\pi}{2} - x \right)}{4 + 3\cos\left( \frac{\pi}{2} - x \right)} \right] dx\]
\[ = \int_0^\frac{\pi}{2} \log\left( \frac{4 + 3 \cos x}{4 + 3\sin x} \right) d x ..............(2)\]
\[\text{Adding (1) and (2)}\]
\[2I = \int_0^\frac{\pi}{2} \left[ \log\left( \frac{4 + 3\sin x}{4 + 3\cos x} \right) + log\left( \frac{4 + 3 \cos x}{4 + 3\sin x} \right) \right] d x \]
\[ = \int_0^\frac{\pi}{2} \log\left( \frac{4 + 3\sin x}{4 + 3\cos x} \times \frac{4 + 3 \cos x}{4 + 3\sin x} \right) d x \]
\[ = \int_0^\frac{\pi}{2} \log1 dx = 0\]
\[Hence\ I = 0 \]

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पाठ 20: Definite Integrals - MCQ [पृष्ठ १२०]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
MCQ | Q 41 | पृष्ठ १२०

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