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2 ∫ 0 √ 4 − X 2 D X - Mathematics

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प्रश्न

\[\int\limits_0^2 \sqrt{4 - x^2} dx\]
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उत्तर

\[\int_0^2 \sqrt{4 - x^2} d x\]
\[ = \int_0^2 \sqrt{2^2 - x^2} d x\]
\[ = \left[ \frac{x}{2}\sqrt{4 - x^2} + \frac{1}{2} \times 2^2 \sin^{- 1} \frac{x}{2} \right]_0^2 \]
\[ = \left[ \frac{x}{2}\sqrt{4 - x^2} \right]_0^2 + 2 \left[ \sin^{- 1} \frac{x}{2} \right]_0^2 \]
\[ = 0 + 2\left( \frac{\pi}{2} - 0 \right)\]
\[ = \pi\]

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Definite Integrals
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पाठ 20: Definite Integrals - Very Short Answers [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 20 Definite Integrals
Very Short Answers | Q 24 | पृष्ठ ११५

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